Q1) \(2\over3\) \(\div\) \(10\over9\) = \(\frac{3}{5}\)
Q1) \(2\over3\) x \(6\over9\) \(\div\) \(10\over18\)= \(\frac{4}{5}\)
Q1) \(2\over3\) x \(9\over10\) - \(6\over10\)= 0
Q2) \(2\over3\) x \(9\over10\) = \(\frac{3}{5}\)
Q2) \(2\over3\) x \(6\over8\) x \(16\over9\)= \(\frac{8}{9}\)
Q2) \(3\over4\) x \(8\over9\) - \(5\over9\)= \(\frac{1}{9}\)
Q3) \(2\over3\) x \(6\over7\) = \(\frac{4}{7}\)
Q3) \(2\over3\) x \(6\over7\) x \(14\over13\)= \(\frac{8}{13}\)
Q3) \(2\over4\) x \(8\over9\) - \(3\over9\)= \(\frac{1}{9}\)
Q4) \(3\over4\) x \(8\over10\) = \(\frac{3}{5}\)
Q4) \(2\over3\) x \(6\over8\) x \(16\over12\)= \(\frac{2}{3}\)
Q4) \(3\over4\) x \(8\over9\) + \(5\over9\)= 1\(\frac{2}{9}\)
Q5) \(2\over4\) x \(8\over9\) = \(\frac{4}{9}\)
Q5) \(2\over3\) x \(6\over7\) x \(14\over13\)= \(\frac{8}{13}\)
Q5) \(2\over4\) x \(8\over10\) x \(20\over14\) + \(4\over10\)= \(\frac{34}{35}\)
Q6) \(2\over3\) x \(9\over10\) = \(\frac{3}{5}\)
Q6) \(2\over3\) x \(6\over7\) x \(21\over13\)= \(\frac{12}{13}\)
Q6) \(3\over4\) x \(8\over9\) + \(7\over9\)= 1\(\frac{4}{9}\)
Q7) \(3\over4\) \(\div\) \(10\over8\) = \(\frac{3}{5}\)
Q7) \(2\over4\) x \(8\over9\) x \(27\over13\)= \(\frac{12}{13}\)
Q7) \(2\over3\) x \(6\over8\) x \(16\over14\) - \(4\over8\)= \(\frac{1}{14}\)
Q8) \(2\over3\) x \(6\over8\) = \(\frac{1}{2}\)
Q8) \(2\over4\) x \(8\over9\) \(\div\) \(9\over18\)= \(\frac{8}{9}\)
Q8) \(2\over3\) x \(6\over7\) x \(14\over10\) + \(6\over7\)= 1\(\frac{23}{35}\)
Q9) \(2\over3\) \(\div\) \(7\over6\) = \(\frac{4}{7}\)
Q9) \(2\over3\) x \(9\over10\) \(\div\) \(13\over20\)= \(\frac{12}{13}\)
Q9) \(2\over3\) x \(6\over7\) + \(5\over7\)= 1\(\frac{2}{7}\)
Q10) \(2\over3\) \(\div\) \(9\over6\) = \(\frac{4}{9}\)
Q10) \(2\over3\) x \(9\over10\) x \(20\over15\)= \(\frac{4}{5}\)
Q10) \(2\over3\) x \(6\over7\) - \(3\over7\)= \(\frac{1}{7}\)